150=3(x^2+10x)/40

Solution for 150=3(x^2+10x)/40 equation:

150=3(x^2+10x)/40

We move all terms to the left:

150-(3(x^2+10x)/40)=0

We multiply all the terms by the denominator


-(3(x^2+10x)+150*40)=0


We calculate terms in parentheses: -(3(x^2+10x)+150*40), so:

3(x^2+10x)+150*40

We add all the numbers together, and all the variables

3(x^2+10x)+6000

We multiply parentheses

3x^2+30x+6000

Back to the equation:

-(3x^2+30x+6000)


We get rid of parentheses

-3x^2-30x-6000=0

a = -3; b = -30; c = -6000;
Δ = b2-4ac
Δ = -302-4·(-3)·(-6000)
Δ = -71100
Delta is less than zero, so there is no solution for the equation